1.

Two soap bubbles, each with a radius 'r' coalesce in a vacuum under isothermal conditions to form a bigger bubble of radius R. Then R is equal to :

Answer»

`2^(-1//2)r`
`2^(1//3)r`
`2^(1//2)r`
`2R`

Solution :Under isothermal conditions there is no CHANGE in SURFACE area
`therefore4pir^(2)+4pir^(2)=4piR^(2)`
`rArrR=sqrt2r`
HENCE the correct choice is (c).


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