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Two solutions of HCI, A and B, haveconcentrations of 0.5 N and 0.1 M respectively. The volume of solutions A and B required to make 2 litres of 0.2 N HCl are |
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Answer» 0.5 L of A + 1.5 L of B Volume of solution B = (2 - X)L `M_1V_1 + M_2V_2 = M(V_1 + V_2)`( for HCl = 0.1 M = 0.1 N) `0.5 xx x + 0.1 (2-x) = 0.2 (2)` `0.5 x + 0.2 - 0.1x = 0.4` `0.4 x = 0.2 ` ` x = (0.2)/(0.4) = 0.5 L` vol. of A = 0.5 L , vol.of B = 2.0 - 0.5 = 1.5L |
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