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Two sound waves y_1= 3sin100 pit and y_2=4 sin102 pit superimpose upon each other find ratio of maximum to minimum intensity of sound? |
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Answer» SOLUTION :`a_1= 3` `a_2= 4I_max/I_min = (a_1 + a_2)^2/(a_1 - a_2)^2 = (3 + 4)^2/(4 - 3)^2 = 49/1` |
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