InterviewSolution
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InterviewSolution
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Two sources of sound `A` and `B` produces the wave of `350 Hz`. They vibrate in the same phase. The particel `P` is vibrating under the influence of these two waves, if the amplitudes at the point P produced by the two waves is `0.3mm` and `0.4mm` then the resultant amplitude of the point `P` will be when `AP-BP=25cm` and the velocity of sound is `350m//sec`.A. `0.7mm`B. `0.1mm`C. `0.2mm`D. `0.5mm` |
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Answer» Correct Answer - D `lamda=(v)/(n)=(350)/(350)=1m=100cm` Also path difference `(Delta x)` between the waves at the point of observation is `AP-BP=25cm`. Hence `Delta phi=(2pi)/(lamda)(Delta x)=(2pi)/(1)xx((25)/(100))=(pi)/(2)` `impliesA=sqrt((a_1)^2+(a_2_^2))=sqrt((0.3)^2+(0.4)^2)=0.5mm` |
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