InterviewSolution
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InterviewSolution
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Two spherical starts A and B emit black body radiation. The radius of A is 400 times that of B and A emits `10^(4)` times the power emitted from B. The ratio `(lambda_(A)//lambda_(B))` of their wavelengths `lambda_(A)` and `lambda_(B)` at which the peaks oc cur in their respective radiation curves is : |
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Answer» Correct Answer - 2 `P=e sigma AT^(-4)` `lambdaT=` constant `P_(A)/P_(B)=(e sigma A_(A) T_(A)^(4))/(e sigma A_(B)T_(B)^(4))=(A_(A) T_(A)^(4))/(A_(B) T_(B)^(4))=r_(A)^(2)/r_(B)^(2). lambda_(B)^(2)/lambda_(A)^(4)` `10^(4)=400^(2).(lambda_(B)/lambda_(A))^(4)` `10^(4)/(16xx10^(4))=(lambda_(B)/lambda_(A))^(4)` `lambda_(A)/lambda_(B)=(16/1)^(1/4)=2` |
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