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Two springs A and B `(K_A = 2 K_B)` are stretched by same suspended weights then ratio of workdone in stretching is -A. `1:2`B. `2:1`C. `1:1`D. `1:4` |
Answer» Correct Answer - A `W=1/2Kx^2, F=-Kx` `W=1/2K.F^2/K^2=F^2/(2K)` `Wprop1/KimpliesW_A/W_B=K_B/K_A=K_B/(2K_B)=1/2` |
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