1.

Two springs A and B `(K_A = 2 K_B)` are stretched by same suspended weights then ratio of workdone in stretching is -A. `1:2`B. `2:1`C. `1:1`D. `1:4`

Answer» Correct Answer - A
`W=1/2Kx^2, F=-Kx`
`W=1/2K.F^2/K^2=F^2/(2K)`
`Wprop1/KimpliesW_A/W_B=K_B/K_A=K_B/(2K_B)=1/2`


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