InterviewSolution
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InterviewSolution
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Two springs have their force constant as `k_(1)` and `k_(2) (k_(1) gt k_(2))`. When they are streched by the same force.A. net work is done in case of both the same springsB. Equal work is done in case of both the springsC. More work is done in case of both the second springsD. More work is done in case of both the first springs |
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Answer» Correct Answer - C `W=(F^(2))/(2k)` If both springs are stretched by same force then `W=prop(1)/(2)` As `k_(1)gt k_(2)` therefore `W_(1) lt W_(2)` i.e, more work is done in case of second spring. |
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