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Two springs, of spring constants `k_(1)` and `K_(2)`, have equal highest velocities, when executing SHM. Then, the ratio of their amplitudes (given their masses are in the ratio `1:2`) will beA. `sqrt(k_(1)//k_(2))`B. `k_(1)//k_(2)`C. `k_(2)//k_(1)`D. `sqrt(k_(2)//k_(1))` |
Answer» Correct Answer - D `(1)/(2)mv^(2) = (1)/(2)K_(1)x_(1)^(2)` `(1)/(2)mv^(2) = (1)/(2)K_(2)x_(2)^(2)` `K_(1)x_(1)^(2) = K_(2)x_(2)^(2)` `(x_(1))/(x_(2)) = sqrt((K_(2))/(K_(1))` |
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