InterviewSolution
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InterviewSolution
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Two stallites A and B revolve round the same planet in coplanar circular orbits lying in the same plane. Their periods of revolutions are 1h and 8h, respectively. The radius of the orbit of A is `10^(4)`km. The speed of B relative to A when they are closed in `kmh^(-1)` isA. `10^(4)pi`B. `2xx10^(4)pi`C. `10^(4)pi//2`D. `4xx10^(4)pi` |
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Answer» Correct Answer - a `(r_(2))/(r_(1))=((T_(1))/(T_(1)))^(2//3)=((8)/(1))^(2//3)=4` `r_(2)=4xxr_(1)` `=4xx10^(4)km` `v_(1)=r_(1)omega_(1)=10^(4)xx(2pi)/(T_(1))` `v_(1)=(2pixx10^(4))/(1)=2pixx10^(4)` ltBrgt `v_(2)=v_(2)omega_(2)` `=4xx10^(4)xx(2pi)/(T_(2))` `=(4xx10^(4)xx2pi)/(8)=pixx10^(4)"km/h"` `V_(AB)=V_(B)-V_(A)` `=2pixx10^(4)-pixx10^(4)=pixx10^(4)(2-1)` `pixx10^(4)`. |
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