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Two stones are thrown into air with speeds 20 m/s, 40 m/s respectively. What accelerations are possessed by the objects? |
Answer» Stone -1 : Initial velocity u = 20 m/s After a time t, it reaches to ground then final velocity v = 0 m/s Acceleration = \(\frac{0\,-\,20}{t}=\frac{-20}{t} \,m/s^2\) Stone – 2 : Initial velocity u = 40 m/s Final velocity v = 0 m/s Acceleration = \(\frac{0\,-\,40}{t}=\frac{-40}{t} \,m/s^2\) |
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