1.

Two stones are thrown into air with speeds 20 m/s, 40 m/s respectively. What accelerations are possessed by the objects?

Answer»

Stone -1 : 

Initial velocity u = 20 m/s

After a time t, it reaches to ground then final 

velocity v = 0 m/s 

Acceleration = \(\frac{0\,-\,20}{t}=\frac{-20}{t} \,m/s^2\)

Stone – 2 : 

Initial velocity u = 40 m/s 

Final velocity v = 0 m/s 

Acceleration = \(\frac{0\,-\,40}{t}=\frac{-40}{t} \,m/s^2\)



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