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| 1. |
Two suplementry angles are in the ratio 3:2.Find the angles. |
| Answer» 1ST ANGLE be = 3×Let the 2nd angle be = 2×sum of supplementry angle = 180so,3× + 2× = 1805× = 180× = 180/5× = 361st angle = 3 × 36 = 1082nd angle = 2 × 36 = 72 | |