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Two tangent galvanometer A and B are identical except in their number of turns. They are connected in series. On passing a current through them, deflections of `60^(@) and 30^(@)` are produced. The ration of the number of turns in A and B isA. `1:3`B. `3:1`C. `1:2`D. `2:1` |
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Answer» As the current and the other factors are sence same for both the galvonometers, so `N alpha tan theta Rightarrow (N_(1))/(N_(2))=(tan 60^(@))/(tan 30^(@)) or (N_(1))/(N_(2))=(sqrt3)/(1//sqrt3)=3:1` |
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