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Two Tapes Can Fill An Empty Tank In 12 And 15 Minutes Respectively. If Both The Taps Are Opened Simultaneously In How Many Minutes The Tank Would Be Full? |
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Answer» Let the two TAPS be A and B. Given, tap a fill the TANK in 12 mins Tap B fill the tank in 15 mins To find the Time taken by both taps opened together to fill the tank: 1/(A + B) = (1/A) + (1/B) => 1/ (A + B) = (1/ 12) + (1/ 15) => 1/ (A + B) = 27 / 180 Taking RECIPROCAL on both sides => A + B = 180 / 27 =>A + B = 20 / 3 mins Let the two taps be A and B. Given, tap a fill the tank in 12 mins Tap B fill the tank in 15 mins To find the Time taken by both taps opened together to fill the tank: 1/(A + B) = (1/A) + (1/B) => 1/ (A + B) = (1/ 12) + (1/ 15) => 1/ (A + B) = 27 / 180 Taking reciprocal on both sides => A + B = 180 / 27 =>A + B = 20 / 3 mins |
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