Two Trains Running In Opposite Directions Cross A Man Standing On The

1.	Two Trains Running In Opposite Directions Cross A Man Standing On The Platform In 27 Seconds And 17 Seconds Respectively And They Cross Each Other In 23 Seconds. The Ratio Of Their Speeds Is?
Answer» LET the speeds of the two trains be a m/sec and B m/sec respectively. Then, length of the first train = 27A meters, and length of the second train = 17b meters. so time = distance/ SPEED. => 23 = (27a+17b) / (a+b). => 23a + 23b = 27a +17b => 23a - 27a = 17b - 23b => -4 a = -6 b => 2 a = 3 b => a/ b= 3/2. Let the speeds of the two trains be a m/sec and b m/sec respectively. Then, length of the first train = 27a meters, and length of the second train = 17b meters. so time = distance/ speed. => 23 = (27a+17b) / (a+b). => 23a + 23b = 27a +17b => 23a - 27a = 17b - 23b => -4 a = -6 b => 2 a = 3 b => a/ b= 3/2.

Two Trains Running In Opposite Directions Cross A Man Standing On The Platform In 27 Seconds And 17 Seconds Respectively And They Cross Each Other In 23 Seconds. The Ratio Of Their Speeds Is?

Answer»

LET the speeds of the two trains be a m/sec and B m/sec respectively.

Then, length of the first train = 27A meters,

and length of the second train = 17b meters.

so time = distance/ SPEED.

=> 23 = (27a+17b) / (a+b).

=> 23a + 23b = 27a +17b

=> 23a - 27a = 17b - 23b

=> -4 a = -6 b

=> 2 a = 3 b

=> a/ b= 3/2.

Let the speeds of the two trains be a m/sec and b m/sec respectively.

Then, length of the first train = 27a meters,