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Two trains starting simultaneously from P&Q towards Q and P resp at 8 am. They cross each other at 12 noon. Train starting from Q, Thereafter takes 6 hours to reach P. On a particular day, the train starting from P, reduced its speed and arrived at Q, 200 minutes late. At what time did the trains cross each other on that day? |
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Answer» `4V_1=6V_2` `V_2=(V_1)/3` `V_1t=V_2 4` `V_1=8/3h` lime(Normal)=`4+8/3=20/3h` Specific lime=`20/3+200/60=10h` `d=V_1*20/3=V*10` `V_1=(2V_2/3)` `d=Vt+V_2t` `20/3V_1=4/3V_1t` `t=5 hours` Multiple time=1P.M. |
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