1.

Two trains starting simultaneously from P&Q towards Q and P resp at 8 am. They cross each other at 12 noon. Train starting from Q, Thereafter takes 6 hours to reach P. On a particular day, the train starting from P, reduced its speed and arrived at Q, 200 minutes late. At what time did the trains cross each other on that day?

Answer» `4V_1=6V_2`
`V_2=(V_1)/3`
`V_1t=V_2 4`
`V_1=8/3h`
lime(Normal)=`4+8/3=20/3h`
Specific lime=`20/3+200/60=10h`
`d=V_1*20/3=V*10`
`V_1=(2V_2/3)`
`d=Vt+V_2t`
`20/3V_1=4/3V_1t`
`t=5 hours`
Multiple time=1P.M.


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