Two trains X and Y start at the same time in the opposite direction fr

1.	Two trains X and Y start at the same time in the opposite direction from two points P and Q and arrive at their destinations 36 and 25 hours respectively after their meeting each other. At what speed does the second train Y travel if the first train travels at 80 km/h.?U GOOD THAN I ALSO GOOD BUDDY ✌❤ HOPE UR SMILE IS A CURVE THAT SETS EVERY THING STRENGTH SO ALWAYS KEEP SMILING ENJOY YOUR BEAUTIFUL DAY ❤✌ FOĽLOW ME THIS IS MY NEW ID ☺
Answer» Let speed of Train B = X 120/x= √(9/16) => x = 4 x 120/3 = 160 km/hr Note : This can be solved without using this formula by using fundamentals of Time, Speed & Distance. Step-by-step explanation: Derivation of formula : Let x be the total distance and t be the time at which the two trains meet. Let s1, s2 are speeds of train A, train B respectively and a & b are the times at which they reach the DESTINATION after they meet. x = t(s1 + s2) ...(1) x = (t + a)s1 ...(2) x = (t + b)s2 ...(3) Solving (1), (2) & (3) t = √(a*b) => Time to meet is the Geometric Mean of individual time after MEETING. => s1/s2 = √(b/a)

Two trains X and Y start at the same time in the opposite direction from two points P and Q and arrive at their destinations 36 and 25 hours respectively after their meeting each other. At what speed does the second train Y travel if the first train travels at 80 km/h.?U GOOD THAN I ALSO GOOD BUDDY ✌❤ HOPE UR SMILE IS A CURVE THAT SETS EVERY THING STRENGTH SO ALWAYS KEEP SMILING ENJOY YOUR BEAUTIFUL DAY ❤✌ FOĽLOW ME THIS IS MY NEW ID ☺

Answer»

Let speed of Train B = X

120/x= √(9/16)

=> x = 4 x 120/3 = 160 km/hr

Note : This can be solved without using this formula by using fundamentals of Time, Speed & Distance.

Step-by-step explanation:

Derivation of formula :

Let x be the total distance and t be the time at which the two trains meet.

Let s1, s2 are speeds of train A, train B respectively and a & b are the times at which they reach the DESTINATION after they meet.

x = t(s1 + s2) ...(1)

x = (t + a)s1 ...(2)

x = (t + b)s2 ...(3)

Solving (1), (2) & (3)

t = √(a*b)

=> Time to meet is the Geometric Mean of individual time after MEETING.

=> s1/s2 = √(b/a)