Two trains X and Y start at the same time in the opposite direction fr

1.	Two trains X and Y start at the same time in the opposite direction from two points P and Q and arrive at their destinations 36 and 25 hours respectively after their meeting each other. At what speed does the second train Y travel if the first train travels at 80 km/h.?koi h ❤☺✌foĺlow me
Answer» Answer: LET speed of Train B = x 120/x= √(9/16) => x = 4 x 120/3 = 160 km/hr Note : This can be solved without using this formula by using fundamentals of TIME, Speed & Distance. Step-by-step explanation: Derivation of formula : Let x be the total distance and t be the time at which the two trains MEET. Let s1, s2 are speeds of train A, train B RESPECTIVELY and a & b are the times at which they reach the destination after they meet. x = t(s1 + s2) ...(1) x = (t + a)s1 ...(2) x = (t + b)s2 ...(3) Solving (1), (2) & (3) t = √(a*b) => Time to meet is the Geometric Mean of individual time after meeting. => s1/s2 = √(b/a) ☺hope that's help you

Two trains X and Y start at the same time in the opposite direction from two points P and Q and arrive at their destinations 36 and 25 hours respectively after their meeting each other. At what speed does the second train Y travel if the first train travels at 80 km/h.?koi h ❤☺✌foĺlow me

Answer»

Answer:

LET speed of Train B = x

120/x= √(9/16)

=> x = 4 x 120/3 = 160 km/hr

Note : This can be solved without using this formula by using fundamentals of TIME, Speed & Distance.

Step-by-step explanation:

Derivation of formula :

Let x be the total distance and t be the time at which the two trains MEET.

Let s1, s2 are speeds of train A, train B RESPECTIVELY and a & b are the times at which they reach the destination after they meet.

x = t(s1 + s2) ...(1)

x = (t + a)s1 ...(2)

x = (t + b)s2 ...(3)

Solving (1), (2) & (3)

t = √(a*b)

=> Time to meet is the Geometric Mean of individual time after meeting.

=> s1/s2 = √(b/a)

☺hope that's help you