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Two triangles BAC and BDC right angled at A and D respectively are drawn on the same base BC and on the same side of BC. If AC and BD intersect at M, prove that AM CM DM BM

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In GIVEN figure TWO triangles BAC and BDC, right angled at A and D respectively, are drawn on the same base BC and on the same side of BC. If AC and DB intersect at P, prove that AP×PC=DP×PB

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