Two unbiased coins are tossed simultaneously. Probability of getting a

1.	Two unbiased coins are tossed simultaneously. Probability of getting at most two heads isA) 1/4B) 1/2C) 3/4D) 1
Answer» Correct option is: D) 1 Probability of getting at most two heads = \(\frac {No \,of \,outcomes \,which \,favours \,at \,most \,two\, heads}{Total \,No \,of \,outcomes}\) = \(\frac 44 =1\) Correct option is: D) 1

Two unbiased coins are tossed simultaneously. Probability of getting at most two heads isA) 1/4B) 1/2C) 3/4D) 1

Answer»

Correct option is: D) 1

Probability of getting at most two heads

= \(\frac {No \,of \,outcomes \,which \,favours \,at \,most \,two\, heads}{Total \,No \,of \,outcomes}\) = \(\frac 44 =1\)

Correct option is: D) 1

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Two unbiased coins are tossed simultaneously. Probability of getting at most two heads isA) 1/4B) 1/2C) 3/4D) 1

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