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Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10 |
Answer» Given: Two unbiased dice are thrown. By using the formula, P (E) = favourable outcomes / total possible outcomes So, we now have to determine the probability of getting the sum of digits on dice greater than 10 Total number of possible outcomes is 62=36 n (S) = 36 Let E be the event of getting same number on all the three dice E = {(5,6) (6,5) (6,6)} n (E) = 3 P (E) = n (E) / n (S) = 3 / 36 = 1/12 |
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