InterviewSolution
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InterviewSolution
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Two unequal masses are ties together with a cord with a compressed spring in between. When the cord is burnt with a match releasing the spring, the two masses fly apart with equalA. (a) Kinetic energyB. (b) SpeedC. (c) MomentumD. (d) Acceleration |
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Answer» Correct Answer - C As `F_(ext)=0`, according to the law of conservation of momentum, `vecP_1+vecP_2=const ant`. but initially both the blocks were at rest, so `vecP_1+vecP_2=0`, i.e., `vecP_2=-vecP_1` i.e., at any instant, the two blocks will have momentum equal in magnitude but opposite in direction (through they may have different values of momentum at different positions). |
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