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Two vertices of a triangle are A (1, 1), B (2, –3). If its centroid is (2, 1) find the third vertex. |
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Answer» Let the co-ordinates of the third vertex be (x, y). Then, Co-ordinates of the centroid are \(\bigg(\frac{1+2+x}{3},\frac{1-3+y}{3}\bigg)\) = \(\bigg(\frac{3+x}{3},\frac{-2+y}{3}\bigg)\) Given, \(\bigg(\frac{3+x}{3},\frac{-2+y}{3}\bigg)\) = (2.1) ⇒ \(\frac{3+x}{3} = 2\) and \(\frac{-2+y}{3} = 1\) ⇒ 3 + x = 6 and – 2 + y = 3 ⇒ x = 3 and y = 5 ∴ Co-ordinates of the third vertex are (3, 5). |
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