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Two wave are represented by equation `y_(1) = a sin omega t` and `y_(2) = a cos omega t` the first wave :-A. leads the second by `pi`B. lags the second by `pi`C. leads the second by `(pi)/(2)`D. lags the second by `(pi)/(2)` |
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Answer» Correct Answer - D `y_(1) = a sin omega t` `y_(2) = a cos omega t = a sin(omega t + pi//2)` `y_(1)` lags `y_(2)` behind by phase `(pi)/(2)` |
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