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Two wavelengths lamda_(1) and lamda_(2) are used in Young's double slit expt. lamda_(1)=430nm. What is the value of lamda_(2) if 4th bright band of one coincides with 6th bright band of the other? |
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Answer» Solution :We have `beta=(Dlamda)/d` and `beta=("DISTANCE of nth bright band")/("No. of bright BANDS")=(x("say"))/n` `:.x/n=(D lamda)/d` i.e. `x=(ND lamda)/d` Her `(n_(1)Dlamda_(1))/d=(n_(2)Dlamda_(2))/d"":.n_(1)lamda_(1)=n_(2)lamda_(2)` `lamda_(2)=(n_(1)lamda_(1))/(n_(2))=(4xx430)/6=286.7nm` |
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