1.

Two waves y_(1) = a sin (omegat - kx) and y_(2) = a cos(omegat - kx) superimpose at a point :

Answer»

The resultant amplitude is `sqrt(2)a`
If l is the intensity of each source then `I_(max) = 2L`
The resultant wave leads `y_(1)` by a phase angle of `(pi)/(4)`
Data insufficient to ARRIVE at options (B) and ("C")

Solution :As the two given WAVES have a phase differencenil we can USE the vector super position principal for the wave amplitudes to find the resulting amplitude and obtain that options (A), (B) and (C) are correct.


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