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Two wires A and B of same mass and material are taken. Diameter of wire A is half of wire B. If resistance of wire A is 24Omega find the resistance of wire B. |
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Answer» Solution :`R=(rhom)/(A^(2)d),(R_(A))/(R_(B))=((r_(B))/(r_(A)))^(4)` `rArr r_(A)=(r_(B))/(2)rArr (R_(A))/(R_(B))=(2)^(4)=16` `therefore R_(B)=(R_(A))/(16)=(24)/(16)="1.5 OHM."` |
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