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Two wires AO and OC carry equal currents i as shown in the figure where |__AOC = theta ,Find the magnitude of the magnetic field at the point P on thebisector of anlge theta at a distance 'r' from O. Assume that the other ends of both wires extend to infinity |
Answer» Solution : The direction of magnetic field due to both the wires AO and OC are out of PAGE of paper Due to wire OC `B = (mu_0i)/(4pid){SIN phi_1 + sin phi_2}` `B = (mu_0i)/(4pisin""theta/2){sin (90 -theta/2) + sin 90}` `B = (mu_0i)/(4pi sin ""theta/2)(1 + cos"" (theta)/(2))` Due to both the wires, the net magnetic field is `B = (2 XX mu_0i)/(4pir sin""theta/2)(1 + cos""theta/2)` `B = (2 xx mu_0i)/(2pir sin""theta/2)(1 + cos""theta/2)` `B = (mu_0)/(2pi) (i)/(r) cot ""(theta)/(4)` |
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