1.

Two wires of equal length and equal diameter and having resisticities rho_(1) and rho_(2) are connected in series. The equivalent resistivity of the combination is .... .

Answer»

`(rho_(1) + rho_(2)) `
`(rho_(1) rho_(2))/(rho_(1) + rho_(2))`
`(rho_(1) + rho_(2))/(2) `
`SQRT(rho_(1) rho_(2))`

SOLUTION :`(rho_(1) + rho_(2))/(2) `
R = `R_(1) + R_(2) `
`(RHO (l + l))/(A) = (rho_(1)l)/(A) = (rho_(2)l)/(A)`
`2 rho = rho_(1) + rho_(2)`
`THEREFORE rho = (rho_(1) + rho_(2))/(2) `


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