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Two wires of equal length and equal diameter and having resisticities rho_(1) and rho_(2) are connected in series. The equivalent resistivity of the combination is .... . |
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Answer» `(rho_(1) + rho_(2)) ` R = `R_(1) + R_(2) ` `(RHO (l + l))/(A) = (rho_(1)l)/(A) = (rho_(2)l)/(A)` `2 rho = rho_(1) + rho_(2)` `THEREFORE rho = (rho_(1) + rho_(2))/(2) ` |
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