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Two wires of equal lengths are bent into the form of two loops. One of the loop is square shaped whereas the other loop is circular. These are suspended in a uniform magnetic field and the same current is passed throgh them. Which loop will experience greater torque? Give reason. |
| Answer» Solution :Torque `tau = n A I B sin theta`, as length of wire is same (say L), for squre loop `A_(s) = (L/4)^2 = (L^2)/(16)` and for circular loop, `A_c = (PI R^2) = pi (L/(2PI))^(2) = (L^2)/(4 pi)` . Obviously , `A_c > A_s`, hence, circular loop will experience greater torque than the square loop. | |