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Two wires of same material having lengths and radii in lhe ratio of 3 : 4 and 3 : 2 respectively are connected in parallel with a potential source of 6V. The ratio of currents flowing through them I_(1) : I_(1)= ..... . |
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Answer» `1:3` `R = (RHO L)/(A) = (rho l)/(pi r^(2)) ` `therefore R prop (l)/(r^(2))` `therefore (R_(1))/(R_(2)) = (l_(1))/(l_(2)) xx ((r_(2))/(r_(1)) )^(2)` `therefore (R_(2))/(R_(1)) = (l_(2))/(l_(1)) xx ((r_(1))/(r_(2)) )^(2) "" ` .... (1) But V = `I_(1) R_(1) = I_(2) R_(2)` `therefore (I_(1))/(I_(2)) = (R_(2))/(R_(1)) "" `..... (2) From equation (1) and (2) , `(I_(1))/(I_(2)) = (4)/(3) xx ((3)/(2))^(2) = (4)/(3) xx (9)/(4) = (3)/(1)` |
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