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Two wires of the same material and length but diameters in the ratio `1:2` are stretched by the same force. The potential energy per unit volume for the two wires when stretched will be of the ratio.A. `1 : 1`B. `2 : 1`C. `4 : 1`D. `16 : 1` |
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Answer» Correct Answer - D `(r_(1))/(r_(2)) = (1)/(2)` `PE` (per unit volume) `= (1)/(2Y)((F)/(A))^(2)` `PE prop 1//A^(2)` `(PE_(1))/(PE_(2)) = (A_(2)^(2))/(A_(1)^(2)) = 16 : 1` |
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