 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | Two wires of the same material and length but diameters in the ratio `1:2` are stretched by the same force. The potential energy per unit volume for the two wires when stretched will be of the ratio.A. `1 : 1`B. `2 : 1`C. `4 : 1`D. `16 : 1` | 
| Answer» Correct Answer - D `(r_(1))/(r_(2)) = (1)/(2)` `PE` (per unit volume) `= (1)/(2Y)((F)/(A))^(2)` `PE prop 1//A^(2)` `(PE_(1))/(PE_(2)) = (A_(2)^(2))/(A_(1)^(2)) = 16 : 1` | |