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TwocarsC_1and C_2movingin thesamedirectionon astraightroadwithvelocities12 m/sand 10 m/srespectively. Whenthe separation betweenthe two is200 m C_2startedacceleratingto avoidcollisionswhatis theminimumaccelerationof car C_2so thattheydon'tcollide . |
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Answer» Solution :Byrelative ` veca _(C_1C_2)= veca_(C_1) - veca_(C_2) =0-a =(-a)` ` vecV_(C_1C_2)= vecV_(c_1) - vecV_(c_2) = 12- 10 =2 m//s ` so byrelativitywe want thecarto stop . ` thereforeV^2 - u^2= 2AS ` `implies0-2^2=- 2 xxa xx 200` `impliesa =1/100m//s^2= 0.1m//s^2= 1 CM //s^2` ` therefore ` Minimumacceelerationneededby CAR`C_2 =1 cm //s^2` |
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