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Twocells ofemfs 1.5 Vand2.0v havinginternalresistance0.2Sigma and0.3 Sigma respectivelyareconnectedin parallel . Calculatethe emfandinternalresistanceof theequivalentcell . |
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Answer» SOLUTION :`E_1 = 1.5 V, R2 = 0.2Omega` `E_2 = 2.0 V, r_2 =0.3Omega` EMF of equivalent cell’ `E=(E_1/r_1+E_2/r_2)/(1/r_1+1/r_2)=(E_1r_2+E_2r_1)/(r_1+r_2)` `=((1.5xx0.3+2xx0.2)/(0.2+0.3))=(0.45+0.40)/(0.5)V=1.7V` INTERNAL RESISTANCE of equivalent cell `1/r=1/r_1+1/r_2=(r_1r_2)/(r_1+r_2)` `=((0.2xx0.3)/(0.2xx0.3))Omega=(0.06)/(0.5)Omega=0.12Omega` |
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