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U - tube moves with a constant speedparallel to the surface of a stationary liquid. The cross - section area of the lower part of the tube lowered into the liquid, is equal to S_(1) and that of thetop part located over the liquid is S_(2). Friction and formation of waves should be neglect difference in heights at both the openings of the tube. The velocity of the liquid coming out of the top part as seen by an observer on the ground will be |
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Answer» `V((S_(1))/(S_(2)))` |
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