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Ultraviolet light of wavelength 280 nm is used in an experiment on photoelectric effect with lithium ( varphi = 2.5 eV) cathode. Find (a) the maximum kinetic energy of the photoelectrons and (b) the stopping potential.

Answer» <html><body><p></p>Solution : (a) The maximum kinetic energy is <br/>` K_max = (hc/lambda)- varphi. ` <br/> `= (<a href="https://interviewquestions.tuteehub.com/tag/1242-1782646" style="font-weight:bold;" target="_blank" title="Click to know more about 1242">1242</a> eV nm/ 280 nm)- 2.5 eV. ` <br/> ` = 4.4 eV - 2.5 eV = 1.9eV. ` <br/>(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) <a href="https://interviewquestions.tuteehub.com/tag/stopping-1228133" style="font-weight:bold;" target="_blank" title="Click to know more about STOPPING">STOPPING</a> potential <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> is given by <br/> ` eV= K_max` <br/>` or, V=(K_max)/<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a> = 1.9 eV/e = 1.9 V.`</body></html>


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