1.

Ultraviolet radiations of 6.2 eV falls on an aluminium surface. Kinetic energy of fastest electrons emitted is (work function = 4.2 eV)

Answer»

`3.2 xx 10^(-21)` J
`3.2 xx 10^(-19)` J
`7 xx 10^(-25)` J
`9 xx 10^(-32)` J

Solution :`K_(max) = h upsilon - W_(0) = 6.2 EV - 4.2 eV`
`= 2.0 eV = 2.0 xx 1.6 xx 10^(-19) j = 3.2 xx 10^(-19) J`


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