-step explanation:Brainly.inWhat is your question?1Secondary School Math 25 points2. Find p(0), p(1) and p(2) for each of the following polynomials:(i) p(y) = y2 – y + 1(ii) p(t)=2+t+2+ -(iii) p(x)= x(iv) p(x)=(x-1)(x+1)please give answer to all questions. I will give my full points.Ask for details Follow REPORT by Karthi98994 23.06.2019AnswersMe · BeginnerKnow the answer? Add it here! erinna Ambitious(i) 1, 1 and 3 respectively.(ii) 4, 5 and 6 respectively.(iii)0, 1 and 2 respectively.(iv) -1, 0 and 3 respectively.Step-by-step explanation:We need to find p(0), p(1) and p(2) for each of the following polynomials.(i)The GIVEN polynomial isP(y)=y^2-y+1Substitute y=0,P(0)=0^2-0+1=1Substitute y=1,P(1)=1^2-1+1=1Substitute y=2,P(2)=2^2-2+1=3Therefore, p(0), p(1) and p(2) are 1, 1 and 3 respectively.Similarly(ii)The given polynomial isP(t)=2+t+2Find p(0), p(1) and p(2).P(0)=2+0+2=4P(1)=2+1+2=5P(2)=2+2+2=6Therefore, p(0), p(1) and p(2) are 4, 5 and 6 respectively.(iii)The given polynomial isp(x)=xFind p(0), p(1) and p(2).P(0)=0P(1)=1P(2)=2Therefore, p(0), p(1) and p(2) are 0, 1 and 2 respectively.(iv)The given polynomial isP(x)=(x-1)(x+1)Find p(0), p(1) and p(2).P(0)=(0-1)(0+1)=-1P(1)=(1-1)(1+1)=0P(2)=(2-1)(2+1)=3Therefore, p(0), p(1) and p(2) are -1, 0 and 3 respectively.