1.

Uncertainty in position of a particle is 0.1587xx10^(-10) m what will be uncertainty in its momentum in kg ms^(-1)?

Answer»

`4xx10^(-23)`
`6.6xx10^(-28)`
`3.1xx10^(-24)`
`6.6xx10^(-24)`

SOLUTION :From Heisenberg.s principle
`Deltax DELTAP=(h)/(2pi)`
`therefore Deltap=(h)/(2pix)`
`=(6.625xx10^(-34))/(6.28xx0.1587xx10^(-10))`
`=6.64736xx10^(-24)~~6.6xx10^(-24)KG ms^(-1)`


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