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Uncertainty in position of a particle is 0.1587xx10^(-10) m what will be uncertainty in its momentum in kg ms^(-1)? |
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Answer» `4xx10^(-23)` `Deltax DELTAP=(h)/(2pi)` `therefore Deltap=(h)/(2pix)` `=(6.625xx10^(-34))/(6.28xx0.1587xx10^(-10))` `=6.64736xx10^(-24)~~6.6xx10^(-24)KG ms^(-1)` |
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