1.

Uncertainty of momentum of a particle is 10^(-30) kg ms^(-1),minimum uncertainty in its position will be……..

Answer»

`10^(-8)m`
`10^(-12)m`
`10^(-16)m`
`10^(-4)m`

Solution :`DELTAX.Deltap=(h)/(2PI)`
`THEREFORE Deltax=(h)/(2piDeltap)`
`=(6.62xx10^(-34))/(6.28xx10^(-30))=1.054xx10^(-4)m~~10^(=-4)m`


Discussion

No Comment Found

Related InterviewSolutions