1.

Under a constant pressure head, the rate of flow of orderly volume flow of liquid through a capillary tube is V, if the length of the capillary is doubled and the diameter of the bore is halved, the rate of flow would become

Answer»

`V//4`
`V//8`
16V
V/32

Solution :Rate of flow of LIQUID is V =`(pipr^(4))/(8etal)`
`thereforeVprop(R^(4))/l`
since DIAMETER is halved so radius is ALSO halved. Also length is doubled.
`thereforeV.` becomes `1/32` times V
So correct choice is (d).


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