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Under ambient conditions, the total number of gases released as products in the final step of the reaction scheme show below is XeF_(6)underset("hydrolysis")overset("Complete")(rarr) underset(underset(underset(underset("Products")(""darr "slow disproportionation in" OH^(-)//H_(2)O))(Q))(""darr OH^(-)//H_(2)O))(""P + "Other products")

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Solution :`XF_(6) + 3H_(2)O underset("hydrolysis")overset("Complete")rarr underset(P)(XeO_(3)) + 6 HF`

`underset(Q)(2 HXeO_(4)^(-)) 2OH^(-) underset(("Slow disproportionation"))overset(OH^(-)//H_(2)O)rarr Xe(g) + XeO_(6)^(4-) (aq) + 2H_(2)O (l) + O_(2)(g)`
Two GASES, i.e., Xe and `O_(2)` are RELEASED, i.e., option (c) is CORRECT.


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