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Under certain circumstances, a nucleus can decay be emitting a particle more massive than an alpha - particle. Consider the following decay processes : ""_(88)^(223)Ra to ""_(82)^(209)Pb + ""_(6)^(14)C ""_(88)^(223)Ra to ""_(86)^(219)Rn + ""_(2)^(4)He Calculate the Q-values for these decays and determine that both are energetically allowed. |
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Answer» Solution :`""_(88)^(223)Ra to ""_(82)^(209)Pb + ""_(6)^(14)C + Q` `:. Q = [m_N ""_(88)^(223)Ra - m_N ""_(82)^(209)Pb - m_N ""_(6)^(14)C] Jc^2` = `{:(223.018497-),(208.981075):}/({:(14.037422-),(14.003242):}/(0.034180))` `= 31.84 MEV` `""^(223)Ra = 223.018497 u` `""^(209)Pb = 208.981075 u` `""_(6)^(14)C = 14.003242 u` `""^(219)RN = 219.009475 u` `""^(4)He = 4.002603` `""_(88)^(223)Ra to ""_(86)^(219)Rn + ""_(2)^(4)He + Q` `Q = [m_N ""_(88)^(223)Ra - m_N ""_(86)^(223)Rn - m_N ""_(2)^(4)He]c^2` = `{:(223.018497-),(219.009475):}/({:(4.009022-),(4.002603):}/(0.006419))` `= 5.98 MeV` |
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