Under certain circumstances, a nucleus can decay by emitting a particle more massive than alpha-particle. Consider the following decay processes: " "_(88)^(223)Ra to " "_(82)^(209)Pb + " "_(6)^(14)C " "_(88)^(223)Ra to " "_(86)^(219)Rn + " "_(2)^(4)He. Calculate the Q-values for these decays and determine that both are energetically allowed.

Under certain circumstances, a nucleus can decay by emitting a particl

1.	Under certain circumstances, a nucleus can decay by emitting a particle more massive than alpha-particle. Consider the following decay processes: " "_(88)^(223)Ra to " "_(82)^(209)Pb + " "_(6)^(14)C " "_(88)^(223)Ra to " "_(86)^(219)Rn + " "_(2)^(4)He. Calculate the Q-values for these decays and determine that both are energetically allowed.
Answer» Solution :For the first PROCESS `Q = [" "_(88)^(223)Ra - " "_(82)^(209)Pb - " "_(6)^(14)C] u= [223.01850 - 208.98107 - 14.00324] u = 0.03419 u = 0.03419 XX 931.5 MEV = 31.85 MeV` For the second process, `Q = [ " "_(88)^(223)Ra - " "_(86)^(219)Rn- " "_(2)^(4)He ] u= [223.01850 - 219.00948 - 4.00260] u = 0.00642 u = 0.00642 xx 931.5 =5.98 MeV` Both processes are energetically possible, because both are exothermic.

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