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Under critical states of a gas for one mole of a gas, compressibility factor is :A. `3//8`B. `8//3`C. `1`D. `1//4`

Answer» Correct Answer - A
For `1mol` of gas `Z = (P_(C)V_(C))/(RT_(C))` (Under critical condition)
But, `P_(C) = (a)/(27b^(2)) , V_(C) = 3b, T_(C) = (8a)/(27Rb)`
`:. Z = ((a)/(27b^(2))) xx (2b)/(R ) xx (27Rb)/(8a) = (3)/(8)`
Hence, (A)`.


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