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Under forward slip condition, translational kinetic energy of a ring is greater than its rotational kinetic energy is this statement true of false? |
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Answer» Under forward up slip condition `vgtRomega` `K_(T)=(1)/(2)mv^(2) `,brgt `K_(R)=(1)/(2)Iomega^(2)=(1)/(2)(mR^(2))omega^(2)` `thereforeK_(T)gtK_(R)` |
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