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Under forward slip condition, translational kinetic energy of a ring is greater than its rotational kinetic energy is this statement true of false?

Answer» Under forward up slip condition `vgtRomega`
`K_(T)=(1)/(2)mv^(2) `,brgt `K_(R)=(1)/(2)Iomega^(2)=(1)/(2)(mR^(2))omega^(2)`
`thereforeK_(T)gtK_(R)`


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