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Under suitable conditions two a-particles can combine to produce a proton and a nuclide of Li^(7). What minimum K.E. must the alpha -particle have in order that the reaction, may proceed. The range of nuclear interaction is 10^(-14)m: |
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Answer» 2.2MeV Then, the `alpha`- particle must have sufficient velocity to come WITHIN the range of nuclear interaction which is `=10^(-14)m` . `1/(4pi epsi_(0)) . q^(2)/d=E("K.E. of INFINITY")` `rArr E=9 xx 10^(9) (4 xx (1.6 xx 10^(-9))^(2))/(10^(-14))` `=5.76 xx 10^(5)eV =0.576 MeV` |
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