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| 1. |
Under the action of a force, a 1 kg body moves, such that its position x as function of time t is given by `x=(t^(3))/(2).` where x is in meter and t is in second. The work done by the force in fiest 3 second isA. `143 J`B. `2430 J`C. `(729)/(8)J`D. `24.3 J` |
| Answer» Correct Answer - C | |