Under the usual notation in probability, P(E) + P (\(\overline{E}\))

1.	Under the usual notation in probability, P(E) + P (\(\overline{E}\)) =A) 0B) 1/2C) 1D) None
Answer» Correct option is: C) 1 P(E) + P (\(\overline E\)) = P (E) + P (not E) = 1 Correct option is: C) 1

Under the usual notation in probability, P(E) + P (\(\overline{E}\)) =A) 0B) 1/2C) 1D) None

Answer»

Correct option is: C) 1

P(E) + P (\(\overline E\)) = P (E) + P (not E) = 1

Correct option is: C) 1

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Under the usual notation in probability, P(E) + P (\(\overline{E}\)) =A) 0B) 1/2C) 1D) None

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