1.

, underset((ii)H^(+)//Delta)overset((i)Br_(2)//KOH)rarr Product is

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Solution :Molar MASS DUE to `CMxx(12)/(100)=12""M=100`
Molar mass due to `OMxx(4)/(100)=16""M=400`
Molar mass due to `SMxx(16)/(100)=32""M=200`
Minimum molar mass should be 400
Number of C-atom =`(400xx12)/(12xx100)=4-"atom"`


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