Unpolarised light falls first on polarizer Pan then on analyzer A. If the intensity o transmitted light from the analyzer is (1)/(8) th the incident unpolarized light what will be th angle between optic axis of P and A?

Unpolarised light falls first on polarizer Pan then on analyzer A. If

1.	Unpolarised light falls first on polarizer Pan then on analyzer A. If the intensity o transmitted light from the analyzer is (1)/(8) th the incident unpolarized light what will be th angle between optic axis of P and A?
Answer» `45^(@)` `30^(@)` `0^(@)` `60^(@)` Solution :`I=(I_(0))/(2) cos^(2) THETA` `(I_(0))/(8)=(I_(0))/(2)cos^(2) theta "" (1)/(2)=cos theta` `(1)/(4)=cos^(2) theta "" :. theta=60^(@)`

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Unpolarised light falls first on polarizer Pan then on analyzer A. If the intensity o transmitted light from the analyzer is (1)/(8) th the incident unpolarized light what will be th angle between optic axis of P and A?

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